How do you multiply $- 2 x (x^{2} - 3)$ $-2x(x^2 - 3)$ ?

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How do you multiply $- 2 x (x^{2} - 3)$ $-2x(x^2 - 3)$ ?

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Answer 1 · 2016-02-12T08:25:13

$- 2 x^{3} + 6 x$ $-2x^3 + 6x$

Explanation:

This is a basic distributive property problem
$- 2 x (x^{2} - 3)$ $-2x(x^2-3)$
Distribute the -2 to both terms in the parenthesis
$- 2 x (x^{2}) - 2 x (- 3)$ $-2x(x^2)-2x(-3)$
$- 2 x^{3} + 6 x$ $-2x^3 + 6x$

Answer 2 · 2016-02-12T20:03:02

$- 2 x^{3} + 6 x$ $-2x^3 +6x$

Explanation:

Using Distributive Property,

$a (b + c) = a b + a c$ $a(b + c) = ab + ac$

Applying the property,

$- 2 x (x^{2} - 3)$ $-2x(x^2 - 3)$

$= - 2 x (x^{2}) - 2 x (- 3)$ $= -2x(x^2) -2x(-3)$

Hence, the answer is,
$= - 2 x^{3} + 6 x$ $= -2x^3 +6x$

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How do you multiply $- 2 x (x^{2} - 3)$ $-2x(x^2 - 3)$ ?

2 Answers

Explanation:

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