How do you integrate #2/x#? Calculus Introduction to Integration Integrals of Rational Functions 1 Answer Steve M · mason m Oct 20, 2016 # int 2/xdx=2lnabsx +C# Explanation: You need to know that # int 1/xdx=ln|x| # So, # int 2/xdx=2lnx + C #, where #C# is the constant of integration. Answer link Related questions How do you integrate #(x+1)/(x^2+2x+1)#? How do you integrate #x/(1+x^4)#? How do you integrate #dx / (2sqrt(x) + 2x#? What is the integration of #1/x#? How do you integrate #(1+x)/(1-x)#? How do you integrate #(2x^3-3x^2+x+1)/(-2x+1)#? How do you find integral of #((secxtanx)/(secx-1))dx#? How do you integrate #(6x^5 -2x^4 + 3x^3 + x^2 - x-2)/x^3#? How do you integrate #((4x^2-1)^2)/x^3dx #? How do you integrate #(x+3) / sqrt(x) dx#? See all questions in Integrals of Rational Functions Impact of this question 31875 views around the world You can reuse this answer Creative Commons License