How do you integrate (1/(16+x^2))(116+x2)? Calculus Introduction to Integration Integrals of Rational Functions 1 Answer Ratnaker Mehta Sep 1, 2016 int 1/(16+x^2)dx=1/4arc tan (x/4)+C∫116+x2dx=14arctan(x4)+C. Explanation: We know that int1/(a^2+x^2)dx=1/aarc tan(x/2)+C∫1a2+x2dx=1aarctan(x2)+C. :. int 1/(16+x^2)dx=1/4arc tan (x/4)+C. Answer link Related questions How do you integrate (x+1)/(x^2+2x+1)? How do you integrate x/(1+x^4)? How do you integrate dx / (2sqrt(x) + 2x? What is the integration of 1/x? How do you integrate (1+x)/(1-x)? How do you integrate (2x^3-3x^2+x+1)/(-2x+1)? How do you find integral of ((secxtanx)/(secx-1))dx? How do you integrate (6x^5 -2x^4 + 3x^3 + x^2 - x-2)/x^3? How do you integrate ((4x^2-1)^2)/x^3dx ? How do you integrate (x+3) / sqrt(x) dx? See all questions in Integrals of Rational Functions Impact of this question 15578 views around the world You can reuse this answer Creative Commons License