How do you graph $y = sin 3 (x + \frac{π}{3})$ $y=sin3(x+pi/3)$ ?

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How do you graph $y = sin 3 (x + \frac{π}{3})$ $y=sin3(x+pi/3)$ ?

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Answer 1 · 2016-11-18T09:34:26

Graph is inserted. Observe period $\frac{2}{3} π$ $2/3pi$ , choosing $x \in [0, \frac{2}{3} π]$ $x in [0, 2/3pi]$ , for one period. y ranges between $\pm (a m p l i t u d e} = \pm 1$ $+-(amplitude}=+-1$ , between the ends $[0, 0] and [\frac{2}{3} π, 0]$ $[0, 0] and [2/3pi, 0]$ .

Explanation:

$y = sin (3 x + π) = - sin (3 x)$ $y = sin (3x+pi)=-sin (3x)$

The graph is inserted.

The period of this sine wave is $\frac{2 π}{3}$ $(2pi)/3$ .

The amplitude is 1.

Sample period: $x \in [0, \frac{2}{3} π]$ $x in [0, 2/3pi]$

Ends for this full wave: $(0, 0) and (\frac{2}{3} π, 0)$ $(0, 0) and (2/3pi, 0)$

graph{y+sin (3x)=0x^2 [-10, 10, -5, 5]}

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How do you graph $y = sin 3 (x + \frac{π}{3})$ $y=sin3(x+pi/3)$ ?

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