How do you graph y=sin3(x+pi/3)?

1 Answer
A. S. Adikesavan
Nov 18, 2016

Graph is inserted. Observe period 2/3pi, choosing x in [0, 2/3pi], for one period. y ranges between +-(amplitude}=+-1, between the ends [0, 0] and [2/3pi, 0].

Explanation:

y = sin (3x+pi)=-sin (3x)

The graph is inserted.

The period of this sine wave is (2pi)/3.

The amplitude is 1.

Sample period: x in [0, 2/3pi]

Ends for this full wave: (0, 0) and (2/3pi, 0)

graph{y+sin (3x)=0x^2 [-10, 10, -5, 5]}

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