How do you graph #y=sin2x-2#?

1 Answer
sankarankalyanam
Oct 23, 2017

graph{sin (2x) - 2 [-10, 10, -5, 5]}

Explanation:

Standard form of equation : #a sin(bx - c) + d#
Given equation # y = sin (2x) - 2#

#a = 1, b = 2, c = 0, d = -1#

Amplitude #a = 1#

#Period =( 2pi )/ b = pi#

Phase shift# = -(c/b) = 0#

Vertical shift # = d = -2#

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