How do you graph #y=sin(x+pi/2)#? Trigonometry Graphing Trigonometric Functions Translating Sine and Cosine Functions 1 Answer Alan N. Mar 15, 2017 #y=cos(x)# Explanation: #sin(a+b) = sin(a)cos(b) + cos(a)sin(b)# Hence: #sin(x+pi/2) = sin(x)cos(pi/2) + cos(x)sin(pi/2)# #= sinx*0 + cosx*1 =cosx# #:.# the graph of #y# is the graph of #cosx# as below: graph{cosx [-6.243, 6.24, -3.12, 3.123]} Answer link Related questions How do you graph sine and cosine functions when it is translated? How do you graph #y=sin ( x -frac{\pi}{2} )#? How do you draw a sketch of #y = 1 + cos (x - pi)# How do you shift and graph #y=-3+sinx#? How do you graph #y=3sin(1/3x+ pi/2)-2#? How do you graph #1/2sin(x-pi)#? How do you graph #-sinx+2#? How do you graph #y=3sin(1/2)x#? How do you graph #y=-2cos((pix)/3)#? How do you graph #y = (1/2)sin(x - pi)#? See all questions in Translating Sine and Cosine Functions Impact of this question 1539 views around the world You can reuse this answer Creative Commons License