How do you graph # y=-sin(x+pi)#? Trigonometry Graphing Trigonometric Functions Translating Sine and Cosine Functions 1 Answer Sonnhard Jun 2, 2018 graph #y=sin(x)# Explanation: we have #sin(x+pi)=sin(x)cos(pi)+sin(pi)*cos(x)=-sin(x)# since #cos(pi)=-1# and #sin(pi)=0# Answer link Related questions How do you graph sine and cosine functions when it is translated? How do you graph #y=sin ( x -frac{\pi}{2} )#? How do you draw a sketch of #y = 1 + cos (x - pi)# How do you shift and graph #y=-3+sinx#? How do you graph #y=3sin(1/3x+ pi/2)-2#? How do you graph #1/2sin(x-pi)#? How do you graph #-sinx+2#? How do you graph #y=3sin(1/2)x#? How do you graph #y=-2cos((pix)/3)#? How do you graph #y = (1/2)sin(x - pi)#? See all questions in Translating Sine and Cosine Functions Impact of this question 1521 views around the world You can reuse this answer Creative Commons License