How do you graph $y = sin (x - 3 \frac{π}{4})$ $y = sin(x -3pi/4)$ ?

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How do you graph $y = sin (x - 3 \frac{π}{4})$ $y = sin(x -3pi/4)$ ?

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Answer 1 · 2015-08-27T10:41:34

Draw the graph for $y = sin (θ)$ $y=sin(theta)$ using a Y-axis and a $θ$ $theta$ -axis;
then replace the $θ$ $theta$ -axis with an x-axis using the same scale as the $θ$ $theta$ -axis but with $\frac{3 π}{4}$ $(3pi)/4$ shifted left to $0$ $0$ .

Explanation:

If we let $sin (x - \frac{3 π}{4}) = sin (θ)$ $sin(x-(3pi)/4) = sin(theta)$
then the period and amplitude remain the same
but
$θ = 0$ $theta=0$ will need to match up with $x = \frac{3 π}{4}$ $x=(3pi)/4$

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How do you graph $y = sin (x - 3 \frac{π}{4})$ $y = sin(x -3pi/4)$ ?

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How do you graph y=sin(x−3π4)y = sin(x -3pi/4)?

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Explanation:

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How do you graph $y = sin (x - 3 \frac{π}{4})$ $y = sin(x -3pi/4)$ ?