How do you graph $y = 3 sec(2x)$ ?

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Answer 1 · 2018-05-06T13:24:27

As below.

$y = A sec (Bx - C) + D " is the standard form of secant function"$

$"Given : " y = 3 sec (2x)$

$"Amplitude is NONE for a secant function"$

$"Period + (2pi) / |B| = (2pi) / 2 = pi$

$"Phase shift " = - C / B = 0$

$Vertical shift " = D = 0$

graph{3 sec (2x) [-10, 10, -5, 5]}

How do you graph y = 3 sec(2x)y = 3 sec(2x)?