How do you graph # y=sin(5/3x)#?

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Answer 1 · 2018-05-02T10:06:30

As below.

Standard form is # y = A sin (Bx - C) + D#

#Given : " y = sin ((5/3) x#

#'Aplitude " = |A| = 1#

#"Period " = p = (2pi) / |B| = (2pi) / (5/3) = (6pi)/3#

#"Phase Shift " = - C / B = 0#

#"Vertical Shift " = D = 0#

graph{sin ((5/3)x) [-10, 10, -5, 5]}