How do you graph #y = -sin(2x)#?
1 Answer
Jun 15, 2015
These are three steps (transformations) that you can apply in every order you want,and you'll obtain
Explanation:
- Start graphing the trig function you know,
#y=sin(x)# .
graph{sinx [-10, 10, -5, 5]}
- Doubling the argument you have a compression in the period, that means that the function double the frequency: if we had the solutions in
#0,pi,2pi,3pi,...# now we have solutions in#0,pi/2,pi,3/2pi,2pi,...#
graph{sin(2x) [-10, 10, -5, 5]}
- The minus sign in front of the function is a reflection on the x-axis, so for each point of the function
#(x,y)->(x,-y)# :
graph{-sin(2x) [-10, 10, -5, 5]}
