How do you graph # y=-sin(1/10x)#?

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Answer 1 · 2018-05-30T16:20:21

Graph inverted on x axis and stretched to a period of #20pi#

#y=-sin(1/10x)#

standard for is:

#y = asin(bx-c)+d#

a = amplitude, #a<0# graph inverts on x axis.

b - horizontal stretch/compression

your c and d are 0

So your graph amplitude #a= -1# so range remains -1 to 1 but the graph is inverted.

your horizontal stretch is #1/10# so the period of your function will be stretched by a factor of 10:

#10*2pi#

graph{-sin(1/10x) [-40, 40, -20, 20]}