How do you graph #y=cos(x-pi/2)#?

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Answer 1 · 2018-07-13T12:35:08

As below.

Standard form of cosine function is #y = A cos (Bx - C) + D#

#y = cos (x - pi/ 2)#

#A = 1, B = 1, C = pi/2, D = 0#

#Amplitude = |A| = 1#

Period #= (2 pi)/ |B| = (2 pi)/ 1 = 2pi#

Phase shift # = -C / B = (-pi/2) / 1 = -pi/2#, #color(red)(pi/2)# to the LEFT.

Vertical Shift #= D = 0#

graph{cos (x-pi/2) [-10, 10, -5, 5]}