How do you graph #y = cos (pi /2) x#?

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How do you graph #y = cos (pi /2) x#?

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Answer 1 · 2015-09-05T14:30:58

The graph looks like:

graph{cos(pi/2*x) [-1.004, 6.79, -1.715, 2.18]}

Explanation:

When you draw a graph of a function #f(x)=cosax#, the amplitude remains unchanged (#<-1;1>#), but the period changes to #T=(2pi)/a#. In this case the period is #4#

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How do you graph #y = cos (pi /2) x#?

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