How do you graph #y=5sin(x-7pi/6) + 3#?

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Answer 1 · 2018-03-24T02:17:13

As below.

Standard form of equation is #y = A sin (Bx - C) + D#

Given equation is #y = 5 sin (x - ((7pi)/6)) + 3#

#Amplitude = |A| = 5#

#"Period " = P = (2pi) / |B| = 2pi#

#"Phase Shift " = P_s = (-C)/ B = ((7pi)/6) / 1 = (7pi)/6, " to the right"##

#"Vertical Shift " = V_s = D = 3#

graph{5 sin (x - ((7pi)/6)) + 3 [-10, 10, -5, 5]}