How do you graph #y=5sin(2x+pi)#?

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Answer 1 · 2018-03-28T02:27:12

As below.

#y = A sin (Bx - C) + D# , where

#Amplitude = |A|, " Period " = (2pi)/|B|, " Phase Shift " = (-C) / B, " Vertical Shift " = D#

Given equation is #y = 5 sin (2x + pi)#

#Amplitude = |A| = 5#

#"Period " = (2pi) / |B| = (2pi)/|2| = pi#

#" Phase Shift " = (-C) / B = (-pi) / 2 = -pi/2 " " color(blue)((pi/2 " to the left")#

#" Vertical Shift = D = 0#

graph{5 sin(2x + pi) [-10, 10, -5, 5]}