How do you graph # y=5+3sin(2x-pi/2)#?

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Answer 1 · 2018-07-21T13:41:26

As below.

#"Standard form of a Sine function is " y = A sin(Bx - C) + D#

#"Given : " y = 3 sin(2x - pi/20 + 5#

#A = 3, B = 2, C = pi/2, D = 5#

#Amplitude = |A| = 3#

#"Period " = (2pi) / |B| = (2pi) / 2 = pi#

#"Phase Shift " = -C / B = -(pi/2) / 2 = - (pi/4), color(crimson)(pi/4 " to the LEFT"#

#"Vertical Shift " = D = 5#

graph{3 sin (2x - pi/2) + 5 [-9.33, 10.67, -1.24, 8.76]}