How do you graph #y=4sin(3x+pi/4)-1#?

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Answer 1 · 2018-03-28T02:39:28

As below.

Standard form of equation is #y = A sin(Bx - C) + D#

Given #y = 4 sin (3x + pi/4) - 1#

#Amplitude = |A| = 4#

#"Period " = (2pi) / |B| = (2pi)/3#

#"Phase Shift " = -C / B = (-pi/4) / 3 = -pi/12, " " (color(blue)((pi/12) " to the left"))#

#"Vertical Shift " = D = -1#

graph{4 sin(3x + (pi/4)) - 1 [-10, 10, -5, 5]}