How do you graph #y=-4cos(x-pi)#? Trigonometry Graphing Trigonometric Functions Translating Sine and Cosine Functions 1 Answer Ratnesh Bhosale Mar 3, 2017 #y=-4cos(x-pi)# Explanation: #y=-4cos(x-pi)# graph{y=-4 cos(x-pi) [-10, 10, -5, 5]} Answer link Related questions How do you graph sine and cosine functions when it is translated? How do you graph #y=sin ( x -frac{\pi}{2} )#? How do you draw a sketch of #y = 1 + cos (x - pi)# How do you shift and graph #y=-3+sinx#? How do you graph #y=3sin(1/3x+ pi/2)-2#? How do you graph #1/2sin(x-pi)#? How do you graph #-sinx+2#? How do you graph #y=3sin(1/2)x#? How do you graph #y=-2cos((pix)/3)#? How do you graph #y = (1/2)sin(x - pi)#? See all questions in Translating Sine and Cosine Functions Impact of this question 2119 views around the world You can reuse this answer Creative Commons License