How do you graph #y=3sin(2x-pi)-1#?

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Answer 1 · 2018-03-19T08:29:47

As below.

Standard form is #y = A sin(Bx -C) + D#

Given : #y = 3 sin (2x - pi) - 1#

#Amplitude = |A| = 3#

#"Period " = P = (2pi) / |B| = (2pi) / 2 = pi#

#"Phase Shift" = P = (-C)/B = pi / 2# #"to the right"#

#"Vertical Shift " = D = -1#

graph{3 sin(2x-pi) - 1 [-10, 10, -5, 5]}