How do you graph #y=2sinpix#?

1 Answer
A. S. Adikesavan
Jul 26, 2018

See graph and details.

Explanation:

#y = 2 sin pix in 2 [- 1, 1 ] = [ -2, 2 ]#

Period = ( 2pi )/pi = 2.

Amplitude = 2.

See graph depicting these aspects.:
graph{(y -2 sin (pi x ))(y^2-4)(x^2-1)=0}[-6 6 -3 3]

Graph for precisely one half.period, #x in [ - 1/2, 1/2 ]#, using the

inverse #x-1/pi arcsin(y/2)=0# that does the truncation:
graph{x-1/pi arcsin(y/2)=0[-1/2 1/2 -2 2] }

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