How do you graph #y=2sin(1/2x)#?

1 Answer
A. S. Adikesavan
Nov 18, 2016

The graph is inserted. The sine wave amplitude is 2 and the period is #4pi#. One full wave is in-between #[-2pi, 0] and [0, 2pi]]#

Explanation:

The period is #(2pi)/(1/2) =4pi#, for one full wave.

For visual effect, choose one period as ^#x in [-2pi, 2pi]#.

The ends of this part are #[-2pi, 0] and [0, 2pi]#

y ranges between #+-(amplitude)=+-2#.

graph{y=2 sin (x/2) [-10, 10, -5, 5]}

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