How do you graph #y=2cos2x#?

1 Answer
Gió
Apr 19, 2015

You can deduce a lot of things from the equation representing your function.

It is a cosine with amplitude of #2# and a length #lambda# (before it repeats itself) that can be found using the #2# in front of #x# as the value of #k# in:

#k=(2pi)/lambda#

giving: #lambda=pi# basically it is a squashed cosine function that instead of going from #0# to #2pi# goes from #0# to #pi#:
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