How do you graph $y=-2-sin(x-pi)$ ?

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Answer 1 · 2018-06-19T06:57:43

As below.

Standard form of sine function is $y = A sin (Bx - C) + D$

$"Given " y = - sin (x - pi) - 2$

$A = -1, B = 1, C = pi, D = -1$

$Amplitude = |A| = |-1| = 1$

$"Period " = (2pi) / |B| = 2pi$

$"Phase Shift " = _C / B = -pi / 1 = -pi, pi " to the left"$

$"Vertical Shift " = D = -2$

graph{- sin(x - pi) - 2 [-10, 10, -5, 5]}

How do you graph y=-2-sin(x-pi) y=-2-sin(x-pi)?