How do you graph #y=1/4sinpix#?

1 Answer
Bill Jorgensen
May 19, 2018

sine has an initial amplitude of 1 so its range is [-1 to 1] but in your function the amplitude is reduced by a factor of #1/4# so it will be a sine wave ranging from #-1/4# to #1/4#

Now the period, normally the period would be #2pi#, but in your case we're adjusting the period input by #pi# so the graph would have a period of 2.

graph{1/4sin(pix) [-0.352, 2.72, -0.59, 0.946]}

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