How do you graph #y=1/4cos3x#? Trigonometry Graphing Trigonometric Functions Translating Sine and Cosine Functions 1 Answer sankarankalyanam May 10, 2018 As detailed Explanation: #y = A cos (Bx - C) + D# Given #y = (1/4) cos x# #A = 1/4, B = 3, C = 0, D = 0# #Amplitude = |A| = 1/4# #"Period " = (2pi) / |B| = (2pi)/3# #"Phase Shift " = -C / B = 0# #"Vertical Shift ' = D = 0# graph{(1/4)cos(3x) [-10, 10, -5, 5]} Answer link Related questions How do you graph sine and cosine functions when it is translated? How do you graph #y=sin ( x -frac{\pi}{2} )#? How do you draw a sketch of #y = 1 + cos (x - pi)# How do you shift and graph #y=-3+sinx#? How do you graph #y=3sin(1/3x+ pi/2)-2#? How do you graph #1/2sin(x-pi)#? How do you graph #-sinx+2#? How do you graph #y=3sin(1/2)x#? How do you graph #y=-2cos((pix)/3)#? How do you graph #y = (1/2)sin(x - pi)#? See all questions in Translating Sine and Cosine Functions Impact of this question 1773 views around the world You can reuse this answer Creative Commons License