How do you graph #y=-1/3cos(x/2)#?

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Answer 1 · 2018-06-28T04:47:22

As below.

#"Standard form of cosine function is ' y = A cos (Bx - C) + D#

#"Given : " -(1/3) cos (x/2)#

#A = -1/3, b = 1/2, C = D = 0#

#Amplitude = |A| = |-1/3\ = 1/3#

#"Period " = (2pi) / |B| = (2pi) / (1/2) = 4 pi#

No vertical and phase shifts as C = D = 0

graph{-(1/3) cos (x/2) [-10, 10, -5, 5]}