How do you graph #y=1/2sin2x#?

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Answer 1 · 2018-03-18T11:00:20

As below.

standard form of equation is #y = a sin(bx -c) + d#

Given : # y = (1/2) sin 2x#

#" Amplitude " = a = 1/2#

#"Period " = P = (2pi) / |b| = (2pi) / 2 = pi#

#Phase Shift" = -c / b = 0, "Vertical Shift " = d = 0#

graph{(1/2) sin (2x) [-10, 10, -5, 5]}