How do you graph #y=1/2cosx+3#?

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Answer 1 · 2018-06-21T15:13:19

your graph is moved up vertically 3 units and its amplitude is cut in half as compared to the parent function #y=cosx#

Use this standard formula to convert from the parent function #y=cosx#

#y=acos(bx-c)+d#

a = amplitude
b = horizontal stretch
c = horizontal shift
d = vertical shift

your function has a amplitude of #1/2# and a vertical shift of #+3#

#y=cosx# has a amplitude of 1 and no shift:

graph{cosx [-10, 10, -5, 5]}

#y=1/2cosx + 3#

So your graph is moved up vertically 3 units and its amplitude is cut in half:

graph{1/2cosx + 3 [-10, 10, -5, 5]}