How do you graph #y = -1/2 sin(pi/3)x#?

1 Answer
sankarankalyanam
Mar 18, 2018

As below

Explanation:

Standard form of equation is #y = a sin(bx -c) + d#

Given : y = -(1/2) sin ((pi/3)x)#

#"Amplitude " = |a| = 1/2#

#"Period " = P = (2pi) / |b| = (2pi) / (pi/3) = 6#

# "Phase Shift " = 0#, @"Vertical Shift " = 0#

graph{-(1/2) sin ((pi/3)x) [-10, 10, -5, 5]}

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