How do you graph #(x-3)^2+y^2=16#?
1 Answer
Dec 26, 2016
Please see below.
Explanation:
As
All points
Hence
graph{(x-3)^2+y^2=16 [-7.37, 12.63, -4.92, 5.08]}
Please see below.
As
All points
Hence
graph{(x-3)^2+y^2=16 [-7.37, 12.63, -4.92, 5.08]}