How do you graph #x^2+y^2-49=0#?

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Answer 1 · 2016-12-03T17:32:45

See answer below.

We compare this to the equation of a circle.

#(x-a)^2+(y-b)^2=r^2#

This is a circle, center #(a,b)# and radius #r#

In the equation

#x^2+y^2=49=7^2#

This is the equation of a circle, center #(0,0)# and radius #=7#

Draw this circle, center at the origin and radius #=7#

graph{x^2+y^2=49 [-18.02, 18.01, -9.01, 9.01]}