How do you graph $x^2+y^2=36$ ?

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Answer 1 · 2016-12-15T10:05:44

Please see below.

$x^2+y^2=36$

$hArr(x-0)^2+(y-0)^2=6^2$

This is nothing but locus of a point that moves so that its distance from point $(0,0)$ is always $6$ .

Hence, $x^2+y^2=36$ is equation of a circle with center at $(0,0)$ and radius $6$ and accordingly we graph it.
graph{x^2+y^2=36 [-14, 14, -7, 7]}

How do you graph x^2+y^2=36x^2+y^2=36?