How do you graph $(x-2)^2+(y-1)^2=4$ ?

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Answer 1 · 2016-12-01T07:19:25

This is a circle, center $(2,1)$ and radius $=2$

$(x-a)^2+(y-b)^2=r^2$

The center is $(a,b)$ and the radius is $r$

$(x-2)^2+(y-1)^2=2^2$

This is a circle, center $(2,1)$ and radius $=2$

Mark the center at $(2,1)$ then with a compass draw a circle of radius $2$

graph{(x-2)^2+(y-1)^2=4 [-5.847, 6.637, -1.98, 4.26]}

How do you graph (x-2)^2+(y-1)^2=4(x-2)^2+(y-1)^2=4?