How do you graph the equation #5x-6y=36#?

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Answer 1 · 2017-05-07T14:41:01

Plot the two intercepts: #(7.2, 0) and (0, -6)# and draw a straight line through them.

If an equation is given in standard form: #ax +by =c#, the easiest way to draw the graph is to use the 'intercept method'

All along the #x#-axis, the #y#-value is #0# and
all along the #y#-axis, the #x#-value is #0#.

To find the #x#-intercept, make #y=0#

To find the #y#-intercept, make #x=0#

The #x#-intercept: #" "5x - 0 = 36" "rarr x = 7.2#

The #y#-intercept:#" "0-6y=36" "rarr y =-6#

Plot the two intercepts: #(7.2, 0) and (0, -6)# and draw a straight line through them.