How do you graph #3x-5y= 10# using the slope and y intercept?

1 Answer
MeneerNask
Feb 5, 2015

You first work this into a standard form #y=ax+b#

Step 1: #x#'s to the right:
#3x-5y=10->-5y=-3x+10#

Step 2: divide everything by #-5# to get the #y#
#(-5y)/(-5)=(-3x)/(-5)+10/(-5)->y=3/5 x-2#

Now your slope is #3/5# and your #y#-intercept is #-2#

Graphing:
One point is #(0,-2)#, the #y#-intercept
Take any #x#-value and plug it in the equation, let's say #5#
this gives you #y=3/5 *5-2=1#, so #(5,1)#
Draw the line:
graph{0.6x-2 [-10, 10, -5, 5]}

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