How do you find the radius of a circle with equation #(x-5)^2+(y-3)^2=r^2# that contains the point at (5,1)?
1 Answer
Aug 23, 2017
The radius will measure
Explanation:
Since
#(5 - 5)^2 + (1 - 3)^2 = r^2#
#0^2 + (-2)^2 = r^2#
#4 = r^2#
#r = 2#
Here is the corresponding graph.
graph{(x - 5)^2 + (y -3)^2 = 2^2 [-10, 10, -5, 5]}
Hopefully this helps!
