How do you find the quotient of #(6b-12)/(b+5)div(12b+18)#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Anjali G Mar 24, 2017 #=frac{b-2}{(b+5)(2b+3)}# Explanation: #frac{6b-12}{b+5}divide(12b+18)# #frac{(6b-12)}{(b+5)}*frac{1}{(12b+18)}# Factor the terms completely: #=frac{color(red)((6))(b-2)}{(b+5)}*frac{1}{color(red)((6))(2b+3)}# #=frac{b-2}{(b+5)(2b+3)}# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 1405 views around the world You can reuse this answer Creative Commons License