How do you find the product $x (3 x^{2} + 4) + 2 (7 x - 3)$ $x(3x^2+4)+2(7x-3)$ ?

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How do you find the product $x (3 x^{2} + 4) + 2 (7 x - 3)$ $x(3x^2+4)+2(7x-3)$ ?

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Answer 1 · 2018-04-26T16:39:42

see below

Explanation:

We have, $x (3 x^{2} + 4) + 2 (7 x - 3)$ $x(3x^2+4) +2(7x-3)$
On further simplification,we get,
$3 x^{3} + 4 x + 14 x - 6$ $3x^3+4x+14x-6$
$3 x^{3} + 18 x - 6$ $3x^3+18x-6$ which is the required expression.

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How do you find the product $x (3 x^{2} + 4) + 2 (7 x - 3)$ $x(3x^2+4)+2(7x-3)$ ?

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Explanation:

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How do you find the product x(3x2+4)+2(7x−3)x(3x^2+4)+2(7x-3)?

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How do you find the product $x (3 x^{2} + 4) + 2 (7 x - 3)$ $x(3x^2+4)+2(7x-3)$ ?