How do you find the product $t (4 t^{2} + 15 t + 4) - 4 (3 t - 1)$ $t(4t^2+15t+4)-4(3t-1)$ ?

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How do you find the product $t (4 t^{2} + 15 t + 4) - 4 (3 t - 1)$ $t(4t^2+15t+4)-4(3t-1)$ ?

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Answer 1 · 2018-04-11T22:53:16

$4 T^{3} + 15 T^{2} - 8 T - 4$ $4T^3 +15T^2 - 8T -4$

Explanation:

$(4 T^{3} + 15 T^{2} + 4 T) - (12 T + 4)$ $(4T^(3) + 15T^2 + 4T) - (12T +4)$
$4 T^{3} + 15 T^{2} + 4 T - 12 T - 4$ $4T^(3) +15T^2 +4T -12T -4$
$4 T^{3} + 15 T^{2} - 8 T - 4$ $4T^3 +15T^2 - 8T -4$

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How do you find the product $t (4 t^{2} + 15 t + 4) - 4 (3 t - 1)$ $t(4t^2+15t+4)-4(3t-1)$ ?

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How do you find the product t(4t2+15t+4)−4(3t−1)t(4t^2+15t+4)-4(3t-1)?

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How do you find the product $t (4 t^{2} + 15 t + 4) - 4 (3 t - 1)$ $t(4t^2+15t+4)-4(3t-1)$ ?