How do you find the product $b (b^{2} - 12 b + 1)$ $b(b^2-12b+1)$ ?

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Answer 1 · 2017-01-08T15:19:00

Multiply each term within the parenthesis by $b$ $color(red)(b)$ See full process below:

Multiply each term within the parenthesis by $b$ $color(red)(b)$ :

$(b \times b^{2}) - (b \times 12 b) + (b \times 1)$ $(color(red)(b) xx b^2) - (color(red)(b) xx 12b) + (color(red)(b) xx 1)$

Now we can use these two rules for exponents to finalize the solution:

$x^{1} = x$ $x^color(red)(1) = x$

$x^{a} \times x^{b} = x^{a + b}$ $x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a)+color(blue)(b))$

$(b^{1} \times b^{2}) - (b^{1} \times 12 b^{1}) + (b^{1} \times 1)$ $(color(red)(b^1) xx b^2) - (color(red)(b^1) xx 12b^1) + (color(red)(b^1) xx 1)$

$b^{1 + 2} - 12 b^{1 + 1} + b^{1}$ $b^(1+2) - 12b^(1+1) + b^1$

$b^{3} - 12 b^{2} + b$ $b^3 - 12b^2 + b$

How do you find the product b(b2−12b+1)b(b^2-12b+1)?