How do you find the product $a (- 8 a^{2} + 2 a + 4) + 3 (6 a^{2} - 4)$ $a(-8a^2+2a+4)+3(6a^2-4)$ ?

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How do you find the product $a (- 8 a^{2} + 2 a + 4) + 3 (6 a^{2} - 4)$ $a(-8a^2+2a+4)+3(6a^2-4)$ ?

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Answer 1 · 2017-08-06T11:33:47

See a solution process below:

Explanation:

First, expand both the terms in parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

$a (- 8 a^{2} + 2 a + 4) + 3 (6 a^{2} - 4) \Rightarrow$ $color(red)(a)(-8a^2 + 2a + 4) + color(blue)(3)(6a^2 - 4) =>$

$(a \times - 8 a^{2}) + (a \times 2 a) + (a \times 4) + (3 \times 6 a^{2}) - (3 \times 4) \Rightarrow$ $(color(red)(a) xx -8a^2) + (color(red)(a) xx 2a) + (color(red)(a) xx 4) + (color(blue)(3) xx 6a^2) - (color(blue)(3) xx 4) =>$

$- 8 a^{3} + 2 a^{2} + 4 a + 18 a^{2} - 12$ $-8a^3 + 2a^2 + 4a + 18a^2 - 12$

Next, group like terms:

$- 8 a^{3} + 2 a^{2} + 18 a^{2} + 4 a - 12$ $-8a^3 + 2a^2 + 18a^2 + 4a - 12$

Now, combine like terms:

$- 8 a^{3} + (2 + 18) a^{2} + 4 a - 12$ $-8a^3 + (2 + 18)a^2 + 4a - 12$

$- 8 a^{3} + 20 a^{2} + 4 a - 12$ $-8a^3 + 20a^2 + 4a - 12$

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How do you find the product $a (- 8 a^{2} + 2 a + 4) + 3 (6 a^{2} - 4)$ $a(-8a^2+2a+4)+3(6a^2-4)$ ?

1 Answer

Explanation:

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How do you find the product a(−8a2+2a+4)+3(6a2−4)a(-8a^2+2a+4)+3(6a^2-4)?

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How do you find the product $a (- 8 a^{2} + 2 a + 4) + 3 (6 a^{2} - 4)$ $a(-8a^2+2a+4)+3(6a^2-4)$ ?