How do you find the product $- 9 g (- 2 g + g^{2}) + 3 (g^{2} + 4)$ $-9g(-2g+g^2)+3(g^2+4)$ ?

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How do you find the product $- 9 g (- 2 g + g^{2}) + 3 (g^{2} + 4)$ $-9g(-2g+g^2)+3(g^2+4)$ ?

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Answer 1 · 2017-07-09T12:51:53

See a solution process below:

Explanation:

First, expand the terms in parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

$- 9 g (- 2 g + g^{2}) + 3 (g^{2} + 4) \Rightarrow$ $color(red)(-9g)(-2g + g^2) + color(blue)(3)(g^2 + 4) =>$

$(- 9 g \times - 2 g) + (- 9 g \times - g^{2}) + (3 \times g^{2}) + (3 \times 4) \Rightarrow$ $(color(red)(-9g) xx -2g) + (color(red)(-9g) xx -g^2) + (color(blue)(3) xx g^2) + (color(blue)(3) xx 4) =>$

$18 g^{2} + (- 9 g^{3}) + 3 g^{2} + 12 \Rightarrow$ $18g^2+ (-9g^3) + 3g^2 + 12 =>$

$18 g^{2} - 9 g^{3} + 3 g^{2} + 12$ $18g^2 - 9g^3 + 3g^2 + 12$

Next, group like terms:

$- 9 g^{3} + 18 g^{2} + 3 g^{2} + 12$ $-9g^3 + 18g^2 + 3g^2 + 12$

Now, combine like terms:

$- 9 g^{3} + (18 + 3) g^{2} + 12$ $-9g^3 + (18 + 3)g^2 + 12$

$- 9 g^{3} + 21 g^{2} + 12$ $-9g^3 + 21g^2 + 12$

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How do you find the product $- 9 g (- 2 g + g^{2}) + 3 (g^{2} + 4)$ $-9g(-2g+g^2)+3(g^2+4)$ ?

1 Answer

Explanation:

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How do you find the product −9g(−2g+g2)+3(g2+4)-9g(-2g+g^2)+3(g^2+4)?

1 Answer

Explanation:

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How do you find the product $- 9 g (- 2 g + g^{2}) + 3 (g^{2} + 4)$ $-9g(-2g+g^2)+3(g^2+4)$ ?