How do you find the product $6 g^{2} (3 g^{3} + 4 g^{2} + 10 g - 1)$ $6g^2(3g^3+4g^2+10g-1)$ ?

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Answer 1 · 2017-02-16T12:06:00

$18 g^{5} + 24 g^{4} + 60 g^{3} - 6 g^{2}$ $18g^5 + 24g^4 + 60g^3 - 6g^2$

By doing the multiplication:

$6 g^{2} (3 g^{3} + 4 g^{2} + 10 g - 1)$ $6g^2(3g^3 + 4g^2 + 10g - 1)$

$18 g^{5} + 24 g^{4} + 60 g^{3} - 6 g^{2}$ $18g^5 + 24g^4 + 60g^3 - 6g^2$

How do you find the product 6g^2(3g^3+4g^2+10g-1)6g2(3g3+4g2+10g−1)6g^2(3g^3+4g^2+10g-1)?