How do you find the product $- 4 d (5 d^{2} - 12) + 7 (d + 5)$ $-4d(5d^2-12)+7(d+5)$ ?

Question

How do you find the product $- 4 d (5 d^{2} - 12) + 7 (d + 5)$ $-4d(5d^2-12)+7(d+5)$ ?

1 Answer

Impact of this question

2109 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-08T13:20:16

See a solution process below:

Explanation:

First, expand the terms in parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

$- 4 d (5 d^{2} - 12) + 7 (d + 5)$ $color(red)(-4d)(5d^2 - 12) + color(blue)(7)(d + 5)$

$(- 4 d \cdot 5 d^{2}) + (- 4 d \cdot - 12) + (7 \cdot d) + (7 \cdot 5)$ $(color(red)(-4d) * 5d^2) + (color(red)(-4d) * -12) + (color(blue)(7) * d) + (color(blue)(7) * 5)$

$- 20 d^{3} + 48 d + 7 d + 35$ $-20d^3 + 48d + 7d + 35$

Now, combine like terms:

$- 20 d^{3} + (48 + 7) d + 35$ $-20d^3 + (48 + 7)d + 35$

$- 20 d^{3} + 55 d + 35$ $-20d^3 + 55d + 35$

Science

Math

Humanities

... and beyond

How do you find the product $- 4 d (5 d^{2} - 12) + 7 (d + 5)$ $-4d(5d^2-12)+7(d+5)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the product −4d(5d2−12)+7(d+5)-4d(5d^2-12)+7(d+5)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find the product $- 4 d (5 d^{2} - 12) + 7 (d + 5)$ $-4d(5d^2-12)+7(d+5)$ ?