How do you find the product $2 p r^{2} (2 p r + 5 p^{2} r - 15 p)$ $2pr^2(2pr+5p^2r-15p)$ ?

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How do you find the product $2 p r^{2} (2 p r + 5 p^{2} r - 15 p)$ $2pr^2(2pr+5p^2r-15p)$ ?

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Answer 1 · 2018-06-18T10:06:56

$\Rightarrow 4 p^{2} r^{3} + 10 p^{3} r^{3} - 30 p^{2} r^{2}$ $color(brown)(=> 4 p^2 r^3 + 10 p^3 r^3 - 30 p^2 r^2$

Explanation:

$2 p r^{2} (2 p r + 5 p^{2} r - 15 p)$ $2 pr^2 ( 2pr + 5p^2r - 15p)$

$\Rightarrow 2 p r^{2} \cdot 2 p r + 2 p r^{2} \cdot 5 p^{2} r - 2 p r^{2} \cdot 15 p, removing the bracket$ $=> 2pr^2 * 2pr + 2pr^2 * 5p^2r - 2pr^2 * 15p, " removing the bracket"$

$\Rightarrow 4 p^{2} r^{3} + 10 p^{3} r^{3} - 30 p^{2} r^{2}$ $color(brown)(=> 4 p^2 r^3 + 10 p^3 r^3 - 30 p^2 r^2$

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How do you find the product $2 p r^{2} (2 p r + 5 p^{2} r - 15 p)$ $2pr^2(2pr+5p^2r-15p)$ ?

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How do you find the product 2pr2(2pr+5p2r−15p)2pr^2(2pr+5p^2r-15p)?

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How do you find the product $2 p r^{2} (2 p r + 5 p^{2} r - 15 p)$ $2pr^2(2pr+5p^2r-15p)$ ?