How do you find the polar coordinate for (3, -5)?

1 Answer
Feb 9, 2016

#sqrt34/_-59^@#

Explanation:

To convert rectangular co-ordinates #(x,y)# into polar co-ordinates #(r,theta)=r/_theta#, we use the transformations

#r=sqrt(x^2+y^2)and theta=tan^(-1)(y/x)#.

So in this particular case we get :

#r=sqrt(3^2+(-5)^2)=sqrt34#

#theta=tan^(-1)(-5/3)=-59^@#

This point is indeed in the 4th quadrant and hence its polar representation is #sqrt34/_-59^@#.