How do you find the indefinite integral of int (x^2-4)/x? Calculus Introduction to Integration Integrals of Rational Functions 1 Answer Roy E. Dec 21, 2016 =1/2x^2-4ln|x|+C Explanation: int(x^2-4)/xdx =intx-4/xdx =1/2x^2-4ln|x|+C Answer link Related questions How do you integrate (x+1)/(x^2+2x+1)? How do you integrate x/(1+x^4)? How do you integrate dx / (2sqrt(x) + 2x? What is the integration of 1/x? How do you integrate (1+x)/(1-x)? How do you integrate (2x^3-3x^2+x+1)/(-2x+1)? How do you find integral of ((secxtanx)/(secx-1))dx? How do you integrate (6x^5 -2x^4 + 3x^3 + x^2 - x-2)/x^3? How do you integrate ((4x^2-1)^2)/x^3dx ? How do you integrate (x+3) / sqrt(x) dx? See all questions in Integrals of Rational Functions Impact of this question 6475 views around the world You can reuse this answer Creative Commons License