How do you find the indefinite integral of #int (2x)/(x-1)^2#?

Related questions

• How do you integrate #(x+1)/(x^2+2x+1)#?
• How do you integrate #x/(1+x^4)#?
• How do you integrate #dx / (2sqrt(x) + 2x#?
• What is the integration of #1/x#?
• How do you integrate #(1+x)/(1-x)#?
• How do you integrate #(2x^3-3x^2+x+1)/(-2x+1)#?
• How do you find integral of #((secxtanx)/(secx-1))dx#?
• How do you integrate #(6x^5 -2x^4 + 3x^3 + x^2 - x-2)/x^3#?
• How do you integrate #((4x^2-1)^2)/x^3dx #?
• How do you integrate #(x+3) / sqrt(x) dx#?