How do you find the exact value of $sin^-1(-sqrt3/2)$ ?

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Answer 1 · 2016-10-06T20:25:05

${- pi / 3, - (2 pi) / 3} + 2 pi cdot ZZ$

$sin^-1 (-sqrt 3 / 2) = x$

$-sqrt 3 / 2 = sin x$

$x_1 = -60º or x_2 = - 180º + 60º$

if $x_i$ is a solution, then $x_i + 2 k pi$ are also solutions. $k in ZZ$

$- pi / 3 + 2 k pi$ or $- pi + pi / 3 + 2 k pi$

How do you find the exact value of sin^-1(-sqrt3/2)sin^-1(-sqrt3/2)?